Question

Calculate the number of vacancies per m^3 for gold at 900 °C. The energy for vacancy formation is 0.93 eV/atom. (density of gold = 19.302 g/cm$^3$, atomic weight of gold = 197.97 g/mol)

          Calculate the number of vacancies per m^3 for gold at 900 °C. The energy for vacancy formation is 0.93 eV/atom. 
(density of gold = 19.302 g/cm$^3$, atomic weight of gold = 197.97 g/mol)

Added by Nicole T.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

06/20/2023

Step 1

1 g/cm^3 = 1000 kg/m^3 Therefore, the density of gold is 19.302 g/cm^3 * 1000 kg/m^3 = 19302 kg/m^3. Show more…

Show all steps

Thanks for your feedback!

- [0/1 Points] DETAILS MY NOTES Calculate the number of vacancies per m^3 for gold at 900 °C. The energy for vacancy formation is 0.93 eV/atom. 6.5 (density of gold = 19.302 g/cm3, atomic weight of gold = 197.97 g/mol) PREVIOUS ANSWERS ASK YOUR TEACHER X (need the answer to two significant figures in units of #vacancies/m^3.) Submit Answer