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[-/4.16 Points] DETAILS MY NOTES KATZPSEF1 7.P.041. ASK YOUR TEACHER Three billiard balls, the two-ball, the four-ball, and the eight-ball, are arranged on a pool table as shown in the figure below. Given the coordinate system shown and that the mass of each ball is 0.150 kg, determine the gravitational field at x = 2 m, y = 0. (Express your answer in vector form.) $\vec{g}$ = m/s$^2$ Need Help? SUBMIT ANSWER 1 m 2 m

          [-/4.16 Points] DETAILS MY NOTES KATZPSEF1 7.P.041. ASK YOUR TEACHER
Three billiard balls, the two-ball, the four-ball, and the eight-ball, are arranged on a pool table as shown in the figure below. Given the coordinate system shown and that the mass of each ball is 0.150 kg, determine the gravitational field at x = 2 m, y = 0. (Express your answer in vector form.)
$\vec{g}$ = m/s$^2$
Need Help?
SUBMIT ANSWER
1 m
2 m

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416 points details my notes katzpsef1 7p041 ask your teacher three billiard balls the two ball the four ball and the eight ball are arranged on a pool table as shown in the figure below giv 46056

Added by Cathy W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

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Solved by Expert Kritika Mishra

06/05/2022

Step 1

674 \times 10^{-11} \text{ N m}^2/\text{kg}^2$ is the gravitational constant and $\hat{r}$ is the unit vector pointing from the point to the mass. Show more…

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[-/4.16 Points] DETAILS MY NOTES KATZPSEF1 7.P.041. ASK YOUR TEACHER Three billiard balls, the two-ball, the four-ball, and the eight-ball, are arranged on a pool table as shown in the figure below. Given the coordinate system shown and that the mass of each ball is 0.150 kg, determine the gravitational field at x = 2 m, y = 0. (Express your answer in vector form.) $\vec{g}$ = m/s$^2$ Need Help? SUBMIT ANSWER 1 m 2 m

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Transcript

00:01 Over here we are given that there are three masses having mass 0 .15 km.

00:08 One is placed like this, like this and like this.

00:13 Each of them having a mass of 0 .15 kilogram.

00:21 All right.

00:25 These both distance are given to us.

00:29 This is a and a is equal to 1 .2.

00:35 This is b and this b is equal to 2 .1 meters.

00:44 We need to calculate the gravitational force on the 8th ball due to other two goals.

00:52 What are the name of balls? this is 8, 2 and 4.

00:56 This ball is 8.

00:58 This is 2 and this is.

01:01 We need to calculate the force on this 8th ball.

01:06 First to this second goal would be in this direction.

01:10 And let us say it's magnitude would be f2 8.

01:13 And force through this would be in this direction.

01:17 Let us say this to be f4 -8, 4x4 on 8.

01:24 So we need to add these two.

01:26 All right.

01:27 So first of all, let us calculate the magnitude.

01:29 Then later we will calculate this angle theta and we will take component of this f -4 -8 and we will write it in the vector form.

01:36 Assuming this is our x -axis, this is our volume.

01:43 F -28 would be g, m -1, m -2, but r square, f28 would be equal to g.

01:52 What is the value of g? value of g is 6 .674 3 into 10 to bar 11, multiplied by 0 .15 into 0 .15 over distance is 1 .2 square...

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