0:00
Hello everyone.
00:01
Let us see the following question.
00:03
So, here is a question where alicyclic compound has to be treated with one unit of grignard reagent which has got two moles of mgbr at the terminal places followed by hydrolysis and then followed by oxidation with this pcc to give a final product.
00:19
We have to find out about the final product in the sequence.
00:23
Let us know about the answer.
00:26
So let me draw the structure first of all.
00:28
There is an ali cyclic component compound with the cyclic chain with a ketone at this point.
00:35
So then we have to take on to the following sequence of reaction.
00:39
In sequence 1, it is treated with the mgbr, okay? 1, 2, 3, 4, 1, 2, 3 4, mg, br, sequence 2, it has to carry on h3o plus and in 3 it has to be taking over pcc.
01:04
We have to find out the final product in the sequence.
01:07
So let us see for the mechanism.
01:14
So we know that in the mechanism there is a oxygen.
01:21
This is a double bond o.
01:24
So we know that this oxygen and this oxygen.
01:28
So there is a lone pair of electron.
01:30
If the bond is taken back by this oxygen, we have a following resonating structure.
01:36
This oxygen would be negatively charged, okay, which is connected to 1, okay, 2, 3, 4th.
01:47
4th place also there is a carbonyl growth which is positive.
01:52
So let me have a resonating structure like this.
01:55
So now i am going to take it to take it forward by treating it with magnesium bromine.
02:00
So, i am having m.
02:03
G.
02:05
Br 1, 2, 3, 4, m.
02:09
G .b .r.
02:11
So, this is a delta minus place which is going to hit this place.
02:17
At the same time, i am having, if the m .g leaves this place.
02:21
So, this particular carbonyl carbon, if it is oxidizing here, this will be delta plus once again, isn't it? so, my in this place, this is delta minus, sorry, this is delta minus.
02:34
So this delta minus is place hitting the delta plus region here.
02:38
So in that case, i would be getting a ring, isn't it? so let me count the number of carbon in the ring.
02:45
So, 1, 2, 3, 4, 5, 6, 7 and 8 membered ring i am getting.
02:57
So, we'll see in which positions i have oxygen.
03:00
So let me write in position 1, no.
03:03
So 1, 2, 3, 4, 5, 6, 7, 8.
03:10
If you have considered this as position 1, there is a ketone.
03:14
This is 2, this is 3, this is 4.
03:17
There is also a keto group here.
03:20
Okay, already the bond was missing.
03:22
So i have a keto group here.
03:24
Then this is 5, 6, 7 and 8.
03:29
So, so much big molecule we have got...