00:01
Hi, here in this given problem there are two similar parts to find a unit vector perpendicular to the given plane.
00:11
Both the parts are exactly identical in procedure.
00:17
So i will be doing only the first one.
00:20
In which there are two vectors, vector a that is 7i cap plus 8 j cap and minus 2 k cap.
00:28
And another vector vector b, this is 9i cap minus 4 j cap minus 5 k cap.
00:38
So using an expression for the cross product, vector product of the two vectors a cross b, that is given as a, b, sine theta into n cap.
00:53
N cap is a unit vector perpendicular to the plane containing a and b.
00:59
So this n cap may be given as a cross b cross product of a and b divided by a b sine theta and actually this a b sine theta.
01:13
This is the magnitude of a cross b...