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To 10.0 mL of a 12.0 M HCl(aq) solution is added 30.0 mL. Then a 5.00 mL aliquot of the dilute solution is removed and this aliquot is diluted further to a final volume of 50.0 mL. What is the final molarity? Report your answer with at least two decimal places but do not write the units. Add your answer Integer, decimal, or E notation allowed Question 10 10 Points What is the molarity of Na in 240.0 mL of a 0.350 M Na$_2$SO$_4$ (aq) solution? Enter your answer with three decimal places. Add your answer Integer, decimal, or E notation allowed

          To 10.0 mL of a 12.0 M HCl(aq) solution is added 30.0 mL. Then a 5.00 mL aliquot of the dilute solution is removed and this aliquot is diluted further to a final volume of 50.0 mL. What is the final molarity? Report your answer with at least two decimal places but do not write the units.
Add your answer
Integer, decimal, or E notation allowed
Question 10
10 Points
What is the molarity of Na in 240.0 mL of a 0.350 M Na$_2$SO$_4$ (aq) solution? Enter your answer with three decimal places.
Add your answer
Integer, decimal, or E notation allowed
        
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To 10.0 mL of a 12.0 M HCl(aq) solution is added 30.0 mL. Then a 5.00 mL aliquot of the dilute solution is removed and this aliquot is diluted further to a final volume of 50.0 mL. What is the final molarity? Report your answer with at least two decimal places but do not write the units.
Add your answer
Integer, decimal, or E notation allowed
Question 10
10 Points
What is the molarity of Na in 240.0 mL of a 0.350 M Na2SO4 (aq) solution? Enter your answer with three decimal places.
Add your answer
Integer, decimal, or E notation allowed

Added by Roberto L.

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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-Question 10 part 1 To 10.0 mL of a 12.0 M HCl (aq) solution is added 30.0 mL. Then a 5.00 mL aliquot of the dilute solution is removed and this aliquot is diluted further to a final volume of 50.0 mL. What is the final molarity? Report your answer with at least two decimal places but do not write the units. Integer, decimal, or E notation allowed -Question 10 part 2 What is the molarity of Na in 240.0 mL of a 0.350 M Na2SO4 (aq) solution? Enter your answer with three decimal places. Integer, decimal, or E notation allowed
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Transcript

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00:01 So to solve for this, we are calculating the malarity of the given solution.
00:08 So you have to remember that malarity is equivalent to the most of the solute over the volume of the solution, which should be in liters.
00:21 So using this formula, let's calculate our unknown here.
00:26 First solution, we have 45 grams of an 8204, so that.
00:31 Sodium sulfate we have 45 .0 grams of an 82s .4 how do we convert this to moles we will divide the molar mass of an 82s .o4 molar mass of sodium sulfate is 142 .0 4 grams per mold of sodium sulfate over the volume of the solution so we have 500 ml it's 5 .0 times centid it are up 2ml so remember malarities in terms of liter so we'll convert ml to liters.
01:03 Kassanml is 1 liter.
01:06 Cancel this, grams.
01:11 And we'll get 0 .634.
01:15 This is moles per liter.
01:20 Okay, and as to the question, how would you prepare the solution? you place first your salute that is sodium sulfate, which is 45 grams.
01:32 Okay so you weigh you put 45 grams of sodium sulfate in the glassware and then you add the solvent okay up to the 500m .m.
01:47 Mark in the glassware okay and then second solution polarity will be equivalent to 1 to 5 grams up this is ethanol c2h 50h convert this to moles by dividing the molar mass of ethanol, 46 .07 grams...
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