00:01
Hello everyone in this question we are going to write products of the given reaction so first reaction they have a given 1 methyl cyclohexanol the react with hbr so now let me write the structure of 1 methyl cyclohexanol this is the structure of 1 methyl cyclohexenol here it is ch3 group here it is 1 methyl cyclohexanol when it is react with hbr in presence of ether in presence of ether here it produced 1 -1 -methyl, 1 -bromo -cycline.
00:34
So this is the product we are going to obtain here.
00:39
Here it is bromine.
00:40
This is our product in this reaction.
00:42
So here, now i'm going to move with second reaction here they have given.
00:45
In second reaction they have given here that is butanol c -h -3, ch2, ch2, ch2, oh -2, bitanol they have given.
00:57
When it is react with so -cl2, here it produces ch3, ch2, ch2, ch2, ch2, cl, that is 1 chlorobutin.
01:10
So in this reaction what happens when butanol is react with socl to it produce 1 chlorobutane.
01:16
And third reaction here they have given that is the reactant is this is our reactant in this case.
01:26
When it is react with nbs, that is in bromosexynomide, in presence of sunlight and and ccl4 it produce, here it produce this compound.
01:40
Here what happens, it produces, here it is bromine is going to be attacks here.
01:45
So here what happens, here bromine is going to be attacks at allelic carbon.
01:49
So nbs is going to produce bromine radical.
01:52
It is going to be attacks allelic carbon.
01:55
So that is why, here, bromine radical is going to be attacked here or here.
02:00
Totally it's going to be attack at allelic position.
02:03
So, this is product in this reaction.
02:07
And fourth reaction here they have given, that is here simple they have given, cyclohexanol they have given.
02:17
Here they have given cyclohexanol.
02:19
When it is react with pbr3, pbr3 in entrance of ether, here it produced, here it produces one bromo cyclohexane...