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Q: Three blocks of masses $m_1 = 5 ext{ kg}$, $m_2 = 2 ext{ kg}$, $m_3 = 10 ext{ kg}$ are placed in contact with each other on a frictionless, horizontal surface as shown in the figure below. A constant horizontal force $F = 102 ext{ N}$ is applied to $m_1$ as shown. Find the magnitude of the force of contact between block $m_2$ and block $m_3$.

          Q: Three blocks of masses $m_1 = 5 	ext{ kg}$, $m_2 = 2 	ext{ kg}$, $m_3 = 10 	ext{ kg}$ are placed in contact with each other on a frictionless, horizontal surface as shown in the figure below. A constant horizontal force $F = 102 	ext{ N}$ is applied to $m_1$ as shown. Find the magnitude of the force of contact between block $m_2$ and block $m_3$.
        
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Q: Three blocks of masses m1 = 5 	ext kg, m2 = 2 	ext kg, m3 = 10 	ext kg are placed in contact with each other on a frictionless, horizontal surface as shown in the figure below. A constant horizontal force F = 102 	ext N is applied to m1 as shown. Find the magnitude of the force of contact between block m2 and block m3.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Three blocks of masses m1 = 5 kg, m2 = 2 kg, m3 = 10 kg are placed in contact with each other on a frictionless, horizontal surface as shown in the figure below. A constant horizontal force F = 102 N is applied to m1 as shown. Find the magnitude of the force of contact between block m2 and block m3.
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Transcript

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00:01 Hello guys in this problem we have three blocks with mass m1 equals 5 kilograms m2 equals 2 kilograms and m3 equals 10 kilograms place in contact with each other now a horizontal force is applied on m1 such that the force f equals 102 neutals now we have to find out the force between m 2 and m 3 for this let's assume m1, m2, m3 as a system.
00:35 And since all the blocks are in contact, let's assume the acceleration of the system is a.
00:41 Now, we can write the acceleration of the system as force on the system over the mass of the system, that is m1 plus m2 plus m3.
00:52 Hence the acceleration equals 102 neutrons over 5 plus 2 plus 10 kilograms.
00:59 Hence we get the acceleration equals 6 meters per second square.
01:07 To find out the force on m2, on m3 by m2, let's draw the free body diagram of m3...
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