8 Ω resistor, $I_2$ be the current through the 20.7 Ω resistor, and $I_3$ be the current through the 13.3 V battery.
Applying Kirchhoff's voltage law to the top loop, we have:
$8.2 - 14.8I_1 = 0$
$I_1 = \frac{8.2}{14.8} = 0.554 A$
Applying Kirchhoff's voltage law
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