00:01
Hello, we know that the force on a charge q in the magnetic field is given by qvvector cross b vector.
00:08
So here b vector is the magnetic field and v vector is the velocity of the charge here.
00:13
So v vector is already given in the equation and that is 3 ikkk plus 2j cap plus 4kkkk.
00:20
And the value of b vector is already given and the value of b vector here that is equal to 3i cap plus 2j cap that is already given here.
00:28
Now, let us put the values of the quantity and the q value that is the charge on an electron, that is equal to minus 1 .6 multiplied 10 to the power minus 19 coulum.
00:37
Now putting all the values of the quantity into the expression here, fb, we are getting that fb vector that is equal to this fv vector is equal to minus 1 .6 multiplied 10 to power minus 19 and multiplied v vector, v vector is 3i -kep plus 2j cap plus 4k cap and multiplied cross product of that with 3 ikep plus 4 j k -kp that would be the magnetic field in this case.
01:04
Now from here we are getting that the value here fv vector uh let us find the cross product of v vector cross b vector uh we are getting that v vector cross b vector that is i cap j -kap k -kap and this is 3 to 4 and this is 3 and this is 2 actually this is 2 jk not uh 4 j -j -kap actually this is 2 j -kap actually this is 2 j -kap this is 2 j cap.
01:30
So 320 and we have to take this cross product.
01:33
And the cross product value is coming out to be 6 ikkp plus 12 j cap plus 0 k cap...