00:01
Hello everyone, we are going to understand this question.
00:05
We are given in the question.
00:10
Mass of hanged object, mass of hanged object that is represented by m1.
00:25
So, m1 is equal to 3 .96 kilogram.
00:32
And distance fallen by the object, distance, fallen by the object, fallen by object that is represented by d which is 0 .372 meter and speed that is represented by u which is 1 .32 meter per second gravitational acceleration that is represented by g which is 9 .3 8 meter per second square and mass of second object that is represented by m2 which is given 5 .37 kilogram.
01:42
First of all let's draw the free body diagram.
01:45
Weight of the first block that is m1 into g which is in downward direction, tension in the string is in upward direction and net acceleration is in downward direction.
01:56
For this block friction force is in left side, tension in the string.
02:01
Is in right side and next net acceleration is in right side.
02:08
So let the net acceleration be a which is given in the acceleration given in the diagram acceleration that is a.
02:23
Now using third equation of motion, using third equation of motion, that is v square is equal to u square plus 2 into a into d.
02:52
Here, substituting the value, final speed is 1 .32, so 1 .32 square and initial speed is 0, plus 2 into value of a that is not given, and value of d that is given 0 .372...