Text: (0,0) is the origin.
CottasrtAotpht MrToTJeE MaiN 040719-14
Ijel-702t
The equation of a circle OABC lying entirely in the first or fourth quadrant is x^2 + y^2 = 2.
The possible coordinates of the origin are (6-5, 1+3), (1-√3, 1+√5), (C), (a-1, 43 = 43), none of these.
The nearest point on the line 3x - 4y = 25 from the origin is (5, -25/4).