00:01
For part a, the cutoff frequency is equal to 1 over 4 pi times square root of lc.
00:06
So that's going to be 1 over 4 pi times 25 times 10 to the negative 3 times 1 times 10 to the negative 6 on a square root.
00:15
And we get a cutoff frequency of 503 .29 hertz.
00:19
For the design impedance, that's equal to square root of l divided by c, which is a square root of 25 times 10 to the negative 3.
00:32
Divided by 1 times 10 to the negative 6, and we get 158 .1 oms.
00:37
For part c, we'd like the characteristic impedance at two different frequencies.
00:43
So at 150 hertz, the characteristic impedance is equal to r0 times a square root of 1 minus fc over f squared.
00:51
So at 150, we'll have 158 .1 times a square root of 1 minus 503 .29 divided by 150 squared, and we get j480 .7 oms.
01:04
At 1 ,500 hertz, we will get, oh, i think actually the answer is 506, not 480, i miscalculated, to j 506.
01:17
0 .4 oms...