00:01
Here in this question we have to calculate the mesh current that is i1 and i2 in the given circuit.
00:06
So circuit is given that is 3 ohm resistor is in connected with the 6 ohm resistor which from here is connected to 8 ohm resistor.
00:13
This is the battery source we are considering that is 12 volt battery source.
00:17
This is another that is 2 of v0 battery source is here we are considering.
00:22
Here this is the current i2 which is moving in the we can say that basically in the clockwise direction in the loop from here.
00:28
So from here from the given figure we can say that given circuit we can apply the kvl from here.
00:35
So basically kirchhoff's current law is what we are considering.
00:39
So this value from here is equals to 7 of i -4 of i1 -4 of i2 become equals to 50 and next will be that is 4 of i1 plus 12 of i2 basically we have to multiply this with the 3 become equals to let's say become equals to 150.
01:00
Let's say this is the equation number 1 and another equation from here will be minus 4 of i1 plus 12 of i2 become equals to 20.
01:10
Let's say this is the equation number 2.
01:12
So from solving equation number 1 and 2 we get the value of i1 that is equals to 10 ampere and from the equation 2 we are considering.
01:20
So i2 multiply by the 12 minus 4 of i1 is equals to 20.
01:25
So simplifying the term plug in to the value of i1 we get the value of i2 that is equals to 5 ampere.
01:30
So here we are having the value of i1 and i2.
01:33
Here we are considering about the voltage which is here across the 4 ohm resistor.
01:37
So this is given as v0 that is equals to 4 of i1 minus i of 8.
01:42
So this from here is equals to v0 that is equals to 4 multiply by 10 minus 5.
01:46
Simplifying the term we get the value of v0 that is equals to 20 volt.
01:49
Now we are considering that is 77 of i2 minus of 8 of i2 become equals to 12.
01:54
Simplifying the term from here we get the value of i2 that become equals to 0 .173 ampere.
02:00
This is the value of the i2 and if we are considering about i1 that is equals to 7 times of i2.
02:05
So the value of i1 in this case is equals to 1 .211 ampere.
02:09
Hence the answer to this question...