00:01
In this question, first of all, i need to calculate the most for sodium hydroxide and concentration of hydrochloric acid.
00:07
So for the first one, it is given in the question that 13 .48 ml of sodium hydroxide needed to neutralize the acl.
00:36
Acl means the hydrochloric acid.
00:40
So, most of noh we can find from here.
00:45
So, modes of sodium hydroxide is equal to its strength, that means its concentration or we can see a polarity, multiplied with volume.
01:04
Volume we have to take in later, so we need to convert this, we need to divide this by 1000 and now we will take this is that amount of volume date and it will be equal to 0 .01348 later.
01:23
So molarity for sodium hydroxide is given 0 .2 molar and volume we just obtained that is 0 .01348 later.
01:41
So it will be called to the modes of sodium hydrohydroxate...