00:01
Our question says that given that mass of empty crucible is equal to 88 .000 grams, we have to find stoichiometric ratio between malachite and coo.
00:20
So the mass of crucible with malachite equal to 98 .000 to the power mass of crucible with malachite is equal to 98 .9 .000 to the power mass of crucible with malachite.
00:36
Crucible and contains after the reaction that is equal to 95 .195 gram.
00:48
Our reaction is co2 co3 oh whole twice in solid phase which gives us 2 coo solid phase plus co2 in gase.
01:12
So the first answer is stoichiometric ratio between malachite and coo is equal to 1 is 2.
01:27
This is our answer for first part.
01:29
For the second part mass of malachite is equal to mass of crucible with malachite minus mass of of empty crucible will put the values 98 .00 minus 88 .00 gram that is 10 .00 grams.
02:11
Now moles of malachite in the experiment is equal to 10 .000.
02:22
Divided by 221 .1 is equal to 0 .04523 moles.
02:35
Now moles of coo formed is equal to 2 multiplied by moles of malachite.
02:46
That is equal to 0 .09046 moles.
02:53
Now the formula for mass of coo produced is mole of coo multiplied by molar mass of coo...