\( 0.8 \mathrm{Hg} \) of Aluminium reacted completely with chlorine gas. calculaite the volume of: chlorine gas used lmokar gasvolume is \( 24 \mathrm{dm}^{3} \), \( A L=27 \) )
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8g. The molar mass of Al is 27g/mol. So, Number of moles of Al = mass / molar mass = 0.8g / 27g/mol = 0.0296 mol From the balanced chemical equation of the reaction between Aluminium and Chlorine, 2Al + 3Cl2 -> 2AlCl3 We can see that 2 moles of Al react Show more…
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