00:01
So to solve for this, first question is the number of moles of carbon monoxide.
00:05
If we have 2 .90 grams of carbon monoxide, convert this to moles by dividing the molar mass of co.
00:13
That's 28 .01.
00:15
Then you have your grams, then moles here.
00:18
So that means we could cancel grams.
00:20
And we'll get 0 .10 .35.
00:23
This is moles of carbon monoxide.
00:27
And then for oxygen gas, number of moles.
00:30
Of 02 if we have 2 .9 .00 grams molar mass of o2 is 32 grams then we have here moles so again you can tell grams and we'll get 0 .09063 this is moles of oxygen gas and then to the second question what's the maximum number of moles of co2 produced based on the given amounts of the reactions of the reactions first, we'll have to identify our limiting reactant.
01:03
So we'll calculate mole ratio.
01:07
So mole ratio in this case will be the number of moles of the reactant divided by the coefficient of that reactant from the balance equation.
01:14
So for carbon monoxide, we have 0 .10 -35 moles divided by the coefficient of co from the balance equation, which is 2 will get 0 .0 -175.
01:26
And then for oxygen gas, we have 0 .090...