Given $M = \begin{bmatrix} 1 & 1 \\ 1 & 2 \end{bmatrix}$ and $N = \begin{bmatrix} 1 & -1 \\ 2 & -1 \end{bmatrix}$, solve for $A$ in the equation $N(A + I)^{-1}M = \frac{1}{2}I.$ Answer: $A = \begin{bmatrix} [-1, -2] \\ [2, -1] \end{bmatrix}$
Added by Krista A.
Close
Step 1
Step 1: Rewrite the equation N(A+I)-1M = 1 -I as N(A+I) - M = 1 - I. Show more…
Show all steps
Your feedback will help us improve your experience
Sri K and 101 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Sodium chloride adopts an FCC structure type. Estimate the lattice energy, ΔU, for NaCl using the Born–Lande equation. The bond length for Na–Cl is 283 pm, and the Madelung constant is 1.7476. The Born exponents of the cation and anion are 7 and 9, respectively.
Sri K.
An emission line of sodium has a wavelength of 330 nm. Calculate the energy of a photon of light emitted in J/atom and the energy emitted per mole of Na atoms in kJ/mol at this wavelength: 6.03x10^-19 J/atom, 3.63x10^5 kJ/mol
Nishant K.
The depression in f.p. of $0.01 \mathrm{~m}$ aqueous solution of urea, sodium chloride and sodium sulphate is in the ratio a. $1: 1: 1$ b. $1: 2: 3$ c. $1: 2: 4$ d. $2: 2: 3$
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD