As shown in the figure below, two masses m1 = 4.30 kg and m2 which has a mass 60.0% that of m1, are attached to a cord of negligible mass which passes over a frictionless pulley also of negligible mass. If m1 and m2 start from rest, after they have each traveled a distance h = 1.70 m, use energy content to determine the following. (a) the speed (in m/s) v of the masses m/s (b) the magnitude (in N) of the tension T in the cord N
Added by Jose Angel B.
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$m_2 = 0.60m_1 = 0.60(4.30 \text{ kg}) = 2.58 \text{ kg}$ Show more…
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