1) \[ 2^{2 x}+3 \times 2^{x}-10=0 \]
Added by Natalie S.
Close
Step 1
So, the equation becomes: \[y^2 + 3y - 10 = 0\] This is a quadratic equation and we can solve it by factoring: \[(y - 2)(y + 5) = 0\] Show more…
Show all steps
Your feedback will help us improve your experience
Regina Hays and 100 other Precalculus educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
$2 x^{3}-2 x^{2}-2 x+1=0$
Limits and Continuity
Continuity
$$ (x+1)^{2}(2 x+3)-(x+1)(2 x+3)^{2}=0 $$
Precalculus Review
Solving Miscellaneous Equations
Solve: $2^{\frac{2}{3} x+1}-3 \cdot 2^{\frac{1}{3} x}-20=0$
Exponential and Logarithmic Functions
Exponential Functions
Recommended Textbooks
Precalculus with Limits
Precalculus
Watch the video solution with this free unlock.
EMAIL
PASSWORD