A particle with charge -5.40 nC is moving in a uniform...

Name: A particle with charge -5.40 nC is moving in a uniform magnetic field B = -(1.24 T)k. The magnetic force on the particle is measured to be F = -(3.80x10^-7 N)i + (7.60x10^-7 N)j. Part B Calculate the x-component of the velocity of the particle. Part C Calculate the y-component of the velocity of the particle. Part D Calculate the scalar product v · F.
Uploaded: 2022-09-11T15:42:51-08:00
Duration: 5 min 6 s
Channel: Adi S
Description: A particle with charge -5.40 nC is moving in a uniform magnetic field B = -(1.24 T)k. The magnetic force on the particle is measured to be F = -(3.80x10^-7 N)i + (7.60x10^-7 N)j. Part B Calculate the x-component of the velocity of the particle. Part C Calculate the y-component of the velocity of the particle. Part D Calculate the scalar product v · F.

A particle with charge -5.40 nC is moving in a uniform magnetic field B = -(1.24 T)k. The magnetic force on the particle is measured to be F = -(3.80x10^-7 N)i + (7.60x10^-7 N)j. Part B Calculate the x-component of the velocity of the particle. Part C Calculate the y-component of the velocity of the particle. Part D Calculate the scalar product v · F.

Transcript

00:01 This question we are given here particle with a charge so we can write here value of charge q which is equal to we are given here is minus 5 .40 nanoculum now the charge is moving in a uniform magnetic field so we are given here a magnetic field b so we can write a magnetic field which is equal to minus 1 .24 tesla in the k k carrot in the z direction and we are given here the magnetic force on a particle so we can write your force which is equal to f which is equal to we can write minus 3 .80 multiply by 10 to minus 7 newton and in this direction is i get it is in the x direction now you can write our white component of force so we can write here 7 .60 multiply by 10 to minus 7 newton is in the x direction is in the direction now we can in this first part of this question we want to find the x component of velocity so we want to find first we will find the x component of velocity and now in the second sub part we want to find the y component of velocity so we want to find y component of velocity of particle now we know the value of velocity so you can write velocity which is equal v x i karad plus v y j karat plus v z k karat we know the value of force so we are using the magnetic force formula so f which is equal to f actor which is equal to we can write q multiply by v multiplied by b so we can write here force so we can write value of force minus 3 .30 multiplied by 10 to minus 7 i karat 10 to minus 7 i carrot 10 to minus 7 i karat plus 7 .60 multiply by 10 to minus 7 jkarrate which is equal to we can write value of q minus 5 .40 we can write 540 multiplied by 10 to minus 9 because this is in nanoculum so we convert into this column by we can write here value of v and b so we can write here multiple value of b so we can write v x i karat plus v y j karat plus v z k k karat now also we just multiply by value of b value of magnetic field so we can write here magnetic field minus 1 .29 k karat now we just simplify this equation and we can write here minus 3 .30 multiplied by 10 to minus 7 i karat plus we can write here 7 .60 multiplied by 10 to minus 7 i kareet 10 to minus 7 j karat which is equal to we can write 5 .40 multiply by 20 to minus 9 multiplied by 1 .29 and into the bracket we can write here vx minus j plus we can write v y karat plus we can write v z0 so by comparing both side of equation and we can write here we can write comparing both sides both sides so we can write 5 .40 by 10 x to minus 9 multiply by 1 .29 multiplied by vx which is equal to we can write 7 .60 multiple by 10 to minus 7 now we just simplify this equation and we can write here vx which is equal to minus 109 .1 meter per second so this is the value of velocity of the velocity of particle a now in the second subpart we want to find the velocity of y so by comparing our both side of equation and we can write here 5 .40 multiple ever tend to minus 9 by 1 .29 vy which is equal to we can write minus 3 .30 multiple by 10 to minus 7...

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