1. (4points). Find the hight of parallelepiped formed by the vectors in space \overrightarrow{a} = 3\hat{i} + 2\hat{j} - 5\hat{k}, \overrightarrow{b} = \hat{i} - \hat{j} + 4\hat{k}, \overrightarrow{c} = \hat{i} - 3\hat{j} + \hat{k} over the base formed by \overrightarrow{b} and \overrightarrow{c}. What is the volume of parallelepiped?
Added by Lourdes B.
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The base is formed by the vectors 6 and -1. We can find the area of the base by taking the cross product of these two vectors. The cross product of two vectors, u and v, is given by the formula: u x v = (u2v3 - u3v2)i + (u3v1 - u1v3)j + (u1v2 - u2v1)k In this Show more…
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