00:01
In the given question we are told that a 1 kg ball moving at a velocity of 12 meter per second collides with a 2 kg ball moving at 24 meter per second in the opposite direction.
00:12
Here we have to calculate the velocity of each ball after the collision if e equals to 2 by 3.
00:19
So in the first case here the value is given m1 is 1 kg, m2 2 kg, u1 is 12, u2 is minus 24 meter per second.
00:36
Now, e is equal to v2 minus v1 divide by u1 minus u2.
00:45
Here we know that conservation of momentum m1 u1, m2 equals to m1 v1 v1 plus m2 v2.
00:57
This is our equation 1, this is our equation 2.
01:02
For the first case according to the equation 1, 1 .12 plus 2 into 24 equals to v1 plus 2 into v2.
01:12
So v1 will be minus 2v2 minus 36.
01:17
Now put the value of v1 into equation 2...