00:01
Hello students, to answer the first question, 4 moles of fe reacts with 3 moles of o2 to produce 2 moles of fe2o3.
00:09
Finding the number of moles for fe which is equal to given mass i .e.
00:14
10 gms divided by molar mass which is 55 .84 and hence given number of moles is 0 .179.
00:26
The number of moles for o2 is given mass i .e.
00:30
2 gms divided by molar mass which is 32 gms per mole and hence number of moles is equal to 0 .0625 of oxygen.
00:44
From the balanced chemical equation, 4 moles of fe requires 3 moles of o2.
00:52
The given number of moles is 0 .179 for fe which will require 3 divided by 4 multiplied by 0 .179 which is equal to 0 .134 moles of o2 which is a large amount as compared to the given number of moles which is 0 .0625 and hence the limiting reagent is fe.
01:24
From the balanced chemical equation, 4 moles of fe was producing 1652 kj of energy.
01:36
The given number of moles is 0 .179 of fe which will produce 1652 divided by 4 multiplied by 0 .179 which is equal to minus 34 .416 kj of energy will be released.
02:02
To answer the second question where the enthalpy of the reaction 2 moles of carbon plus 1 mole of h2 to produce 1 mole of ca2h2 is to be determined from the given 3 reaction.
02:15
As 2 moles of carbon is used multiplying the second equation by 2 as 1 mole of h2 is used and hence adding the third equation as 1 mole of c2h2 is the product but in the first reaction it is a reactant and hence inversing the reaction 1 will give the enthalpy of reaction for the given chemical reaction...