1. A block of mass of 2 kg slides on an inclined plane that makes an angle of 30° with the horizontal. The coefficient of friction between the block and the surface is 0.87. What force should be applied to the block so that it moves down without any acceleration?
Added by Fabio Y.
Step 1
First, let's draw a diagram to visualize the situation. We have an inclined plane with an angle of 30° with the horizontal. The block of mass 2 kg is placed on this inclined plane. Show more…
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A block of mass 2 kg slides down an inclined plane which makes an angle 30° with the horizontal. The coefficient of friction between the block and the surface is root 3/2 (i) What force must be applied to the block so that it moves down the plane without acceleration ? (ii) What force should be applied to the block so that it moves up without any acceleration ?
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A block of mass $2, \mathrm{~kg}$ rest on a plane inclined at an angle of $30^{\circ}$ with the horizontal. The coefficient of friction between the block and the surface is 0.7. What will be the frictional force acting on the block? (a) $10.3 \mathrm{~N}$ (b) $23.8 \mathrm{~N}$ (c) $11.9 \mathrm{~N}$ (d) $6.3 \mathrm{~N}$
If the mass of the block is 2 kg and the plane is at an angle of 30º, determine the magnitudes of the known forces. Be sure to think about who has components. What acceleration will the block have if the plane is frictionless? Find the speed of the block 2.0s after being released from rest. What is the minimum coefficient of friction needed to keep the block from moving?
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