Question

1) A certain pollster company finds in a survey of 30 voters that a presidential candidate is favored to win with 51% of the votes. Construct a 99% confidence interval for the true proportion of all voters in favor of the candidate. $n = 30$ $p = 0.51$ $0.51 \pm 2.576 \times 0.0913$ $0.51 \pm 0.2352$ $[0.2748, 0.7452]$ [0.27, 0.75]$ we are 99% confident that the true proportion of all voters in favor of the candidate is between 0.27 and 0.75. 2) If the pollster from problem 1 wanted to construct a 99% confidence interval showing her candidate is favored by a majority, how many people should she survey?

          1) A certain pollster company finds in a survey of 30 voters that a presidential candidate is favored to win
with 51% of the votes. Construct a 99% confidence interval for the true proportion of all voters in favor
of the candidate. $n = 30$ $p = 0.51$
$0.51 \pm 2.576 \times 0.0913$
$0.51 \pm 0.2352$
$[0.2748, 0.7452]$
[0.27, 0.75]$
we are 99% confident that the true proportion
of all voters in favor of the candidate is
between 0.27 and 0.75.
2) If the pollster from problem 1 wanted to construct a 99% confidence interval showing her candidate is
favored by a majority, how many people should she survey?

1) A certain pollster company finds in a survey of 30 voters that a presidential candidate is favored to win
with 51% of the votes. Construct a 99% confidence interval for the true proportion of all voters in favor
of the candidate. n = 30 p = 0.51
0.51 ± 2.576 × 0.0913
0.51 ± 0.2352
[0.2748, 0.7452]
[0.27, 0.75]we are 99% confident that the true proportion
of all voters in favor of the candidate is
between 0.27 and 0.75.
2) If the pollster from problem 1 wanted to construct a 99% confidence interval showing her candidate is
favored by a majority, how many people should she survey?

Added by Brian G.

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