00:01
High, a nitric acid solution is given which is 29 .94 % by mass nitric acid.
00:06
It means that if the total mass of solution is 100 grams, then this solution has 29 .94 grams of nitric acid and remaining 70 .06 gram water.
00:27
First we need to calculate the molality of this solution.
00:30
The formula for molality is moles of solute divided by mass of solvent in kg.
00:38
As the mass of nitric acid is less than the mass of water, that means nitric acid is a solute and water is a solvent.
00:46
So first we need to calculate the moles of nitric acid.
00:50
Moles are calculated as mass divided by the molar mass of nitric acid, which is 63 .01 gram per mole.
01:00
Thus, moles of nitric acid present are 0 .475 moles.
01:06
Mass of solvent is 70 .06 gram but we want it in kg.
01:13
Therefore, 70 .06 multiplied 10 to the power minus 3.
01:18
Kg is the mass.
01:21
Finally, we can calculate the molality.
01:24
0 .475 moles divided by 70 .06 multiplied by 10 risk to the power minus.
01:30
3 kg and the molality comes out to be 6 .78.
01:35
In second part we need to find the molarity of the solution.
01:40
Mularity is moles of solute...