00:01
Yes, students, we have to draw the molecular orbital diagram of o2 minus and n2, 2 plus.
00:06
And we have to discuss about their bond order and magnetic properties.
00:11
Now let us draw the molecular orbital diagram of oxygen.
00:14
We know oxygen is having 8 electrons.
00:17
So 2 oxygen atoms means we have 16 electrons.
00:23
And they are arranged in oxygen atom, the electronic conflation of oxygen is 8, that is 1 ,000 2p 2 and 2 p sorry 2 s 2 1 s 2 2 2 and 2 p 4 now so far as our molecular orbital theory is concerned a molecular orbital diagram is concerned let us draw the diagram we have here this is 1 s then let this be 2 s then we are having 2 p now here 1 s have one orbital, so they will mix to form two molecular orbitals.
01:21
One is bonding, the other one is anti -bonding.
01:25
Similarly, p -orbital is having p -suff cell is having three orbitals.
01:31
Here also, we have three orbitals here, one orbital each.
01:38
Now these three orbitals, 3 plus 3, 6, they will form 6 molecular orbitals.
01:44
So we'll like this, let us write, one, two, three.
01:59
Similarly, we'll have here, so to 16 electrons.
02:15
Now, we'll arrange the orbitals here.
02:19
One bonding, anti -binding, bonding, bonding, anti -bonding, bonding, two anti -bonding, sorry, bonding all are bonding, this is anti -bonding, and here, these two, bonding, anti -bonding, these three.
02:44
Now we'll arrange the electrons.
02:47
Here we'll have two electrons, 1 s2, 2 s2, 2 px1, 2py1, 2pz, 2 6, so 2 plus 2 4, 2 6 to 8, right.
03:00
So here also like that, 8 electrons, 8 electrons.
03:06
Now i'll arrange them in the molecular orbitals, so 4 electrons, 4, this is also 4, now 16 electrons 18 over then here then so this is o 2 2 plus 2 4 plus 2 6 8 10 10 plus 4 plus 14 plus 16 electrons now but in our question it is o 2 minus so o 2 minus means 1 electron extra so o 2 minus means it becomes o 2 minus means it becomes 17 electrons so when 17 electrons means one electron will be paired here so we'll have here like this 17 electrons now if we calculate the bond order bond order we are having bonding electrons 2 plus 2 4 plus 6 plus 4 10 minus anti -binding electrons 2 plus 2 4 3 7 divided by 2 so it is coming 1 .5 the molecule let's total names sigma 1 s, sigma star 1s, sigma 2s, sigma star 2s, this is sigma to p z, this is pi to p x, this is pi 2 p x, this is pi 2 p y, this is pi star to p x, this is pi star to p y, and this is sigma star to p z.
04:53
So, this is how electrons are arranged in 02 minus.
04:59
Now here if we see it is having one unpaid electron, therefore it is paramagnetic.
05:07
It is paramagnetic.
05:10
Now coming to n2 plus, n2 2 plus, let us see its diagram, n2 2 plus.
05:24
So let us draw first n2, then we'll go to n to 2 plus.
05:27
Now, nitrogen is having 7 electrons 1 s 2, 2 s 2 and 2p 3...