00:01
In this video we will discuss two sub -problems such that here the value of time for the third unit denoted by t3 is equal to 16 hours and the learning rate denoted by l will be here equal to 90 percentage or it is here 0 .90.
00:22
Therefore, the learning curve formula is going to be here tn and this is equal to t1 multiplied with n raised to the power it is log l and here the base is 2.
00:37
And we need to calculate the time for the 12th unit.
00:41
But firstly we will use the given information such as t3 is equal to t1, now it is 3 raised to the power it will be log and then it is 0.
00:52
0 .90 to the base 2 and with the help of this particular equation we will try to calculate the value of t 1 so t 1 will be equals to it is 16 divided by we are having 3 and then it is log 0 .90 to the base 2 so now we will use this value to calculate the value of t 12 and it is here t 1 now the n value will be 12 raised to the power it is logarithm of 0 .90 to the base 2.
01:27
So if we plug in the value of t1 here, then t12, that is time for the 12th unit, will be approximately 12 .96 hours.
01:38
And we have obtained the answer for the first part of this very problem.
01:43
And now we will solve the second sub -problem.
01:46
And in the second part, we need to calculate the value of time for the first part, the third unit.
01:53
So let us write over here that the time for the second unit denoted by t2 will be equal to 30 and then it will be here hours.
02:04
Now the time for the fourth unit will be equal to 21 and then it is here hours...