00:01
So we have given here two structures with studio chemistry and we have to name them.
00:07
First of all, we have given a cyclohexane like this, cyclohexane ring like this.
00:18
Bromo atom is a test.
00:22
Methyl group is a test, okay? above the plane, both are above the plane and then we have another methyl group below the plane.
00:33
Among bromo and methyl group, bromo should be given the first position, okay, according to the alphabetic order.
00:41
So this is 1, 2, 3.
00:44
Now we have to find the stereochemistry also.
00:48
So here we have hydrogen atom below the plane.
00:52
Okay.
00:53
So this carbon atom containing bromogro group, hydrogen atom, and then it is attached to two other carbon atom.
01:00
Okay.
01:00
Now here directly this carbon attacks to promo group okay so this has a greater atomic number okay so that's why and greater atomic mass also okay so this will be given the more priority okay first priority is given to this bromogrope least priority is given to this hydrogen because this has atomic number one only and then we have this carbon attached to this methyl group containing carbon atom and then we have this carbon atom attached to another carbon atom so on the basis of that if i give the priority so first priority is to the bromogroop then second to this third to this and fourth to this so this will be like one then two three and four and four okay so this will be like one then two three and four okay so this will be like this clockwise okay so this has r configuration okay for this carbon we have two methyl groups one is about the plane one is down the plane okay and now one is attached to a carbon atom which is to further carbon atom containing gromogro group and another is also a test with carbon atom further attached to carbon atom and then further to carbon atom containing bromogro...