00:01
Hello everyone, and this lesson will solve a ranking cycle problem by tracking energy at four key states.
00:07
We label turbine in light at state 1, turbine x, s state 2, condenser xs state 3, and pump xs state 4.
00:16
From steam table values, we use h1 is equal to approximately 3425 kilojoules per kilogram at 100 bar and 520 degrees celsius, and h3 is equal to approximately 419 kilojoules per kilogram for saturated liquid at 1 bar.
00:30
Next, we account for turbine inefficiency.
00:34
We first estimate the isotropic turbine exit entope at 1 bar as h2s equals approximately 2393 kilojoules per kilogram, then apply it at t equals h1 minus h2 over h1 minus h2s.
00:51
Solving gives h2 is equal to approximately 2589 kilojoules per kilogram, which sets the real turbine work output.
00:57
So we handle the pump and boil a heat input.
01:00
The pump work is approximately, well it's approximated by wp equals v delta p over a to p.
01:10
Using v is equal to approximately 0 .00143 meters cube per kilogram for saturated liquid near one bar and delta p equals to approximately 9900 kilopascals, giving wp equals to approximately 13 .2 kilojoules per kilogram.
01:25
Then h4 is equal to approximately h3 plus wp, that's 432 kilojoules per kilogram, and the boiler heat input is qn equals h1 minus h4, that's 2993 approximately kilojoules per kilogram...