1. A particular cell system using FDD has the following...

1. A particular cell system using FDD has the following characteristics: Cluster size = 7, cells are of uniform size User density = 100 users/sq.km Allocated frequency spectrum = 900 – 949 MHz Bit rate required per user = 10 Kbps uplink and 10 kbps downlink Modulation code rate = 1 bps/Hz a) How much BW is available per cell? b) How many users per cell can be supported? c) What is the cell area? d) Assuming circular cells, what is the cell radius?

Transcript

00:01 So here in this question we are given the density that is equals to 1000 users per square kilometer allocated frequency spectrum is given which is from 900 to 949 megahertz and bit rate required per user bit rate required per user is given that is equals to 10 kbps uplinks of 10 kbps downlinks and the modulation code rate is given that is equals to 1 bps per hertz.

00:36 So in the first part of the question we need to find out the bw which is available per cell.

00:40 So here as we are having the value of the cluster size that is equals to 7.

00:46 So using all this value we are considering about the bm that is band width which is available per cell is given by the formula that is equals to total bw total bandwidth which is divided by the number of cells.

01:07 So here we are having the value of total bw that is total bandwidth which is from 900 to 949 megahertz that is 49 megahertz.

01:18 So number of cell in the cluster is given that is equals to 7.

01:23 So the ratio of bandwidth per cell become equals to 49 of m divided by 7 that is equals to 7 mega hertz and for the uplink bw per cell become equals to 7 divided by 2 that is equals to 3 .5 megahertz and similarly for the downlink the value of bw by cell become equals to 3 .5 megahertz.

01:51 So this is the answer to the part a of the question.

01:55 Now we are considering about the part b of the question where we need to find out the value of how many users per cell can be supported.

02:02 So number of users supported per cell is equals to 3 .5 megahertz which is divided by the 10kbps.

02:18 So this become equals to 3 .5 multiplied by the 10 raised to the power 6 which is divided by 10 multiplied by the 10 raised to the power 3...

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