A point on the rim of a 0.30 m-radius rotating wheel has a tangential speed of 5.0 m/s. What is the tangential speed of a point 0.20 m from the center of the same wheel? a. 1.0 m/s b. 0.50 m/s c. 3.3 m/s d. 17 m/s 2. What centripetal force does an 80.0 kg passenger experience when seated 10.0 m from the center of a Ferris wheel whose angular speed is 0.500 rad/s? a. 2.00 N b. 24.5 N c. 400 N d. 200 N
Added by Benjamin G.
Step 1
Step 1: The tangential speed of a point on a rotating wheel is given by the formula \(v = r\omega\), where \(v\) is the tangential speed, \(r\) is the radius of the wheel, and \(\omega\) is the angular speed of the wheel. Show more…
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