1. A potential difference of 5000. V is applied to two parallel metal plates separated by a distance of 10.0 cm as shown in the following diagram. (4 points) a. Calculate the intensity of the electric field between the plates. b. Determine the size of the force on a charge of +2 C placed in the field
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The intensity of the electric field (E) between the plates can be calculated using the formula E = V/d, where V is the potential difference and d is the distance between the plates. So, E = 5000 V / 0.1 m = 50000 N/C. b. The force (F) on a charge in an Show more…
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