00:01
In this question we are given an inductance resistance circuit.
00:07
In the first question we are asked, we are given the time constant toe is 3 .4 seconds.
00:15
The inductance is 450 entry and we have to find out the resistance in the circuit.
00:22
As we know that in an lr circuit the time constant toe is equal to l by r from the from this, resistance r will be equal to l by tau.
00:38
Substituting the values, we get 450 henry divided by 3 .4 seconds.
00:47
From this we get a resistance will be 132 .35 o.
00:57
So option c is the right answer.
01:04
Now, in the second part, we had given the rate of change of current at the time, da by dt is given us 0 .034 amoe per second.
01:22
Here also, we are asked to take the inductance from the first question that is 450, henry.
01:29
Now, we have to find out the potential difference across the inductor...