00:01
What is the molarity of this strontium hydroxide solution? so we know we have 10 .40 grams of it, of sroh2, we know it's dissolved in 59 milliliters.
00:13
So our first job is to convert this to moles.
00:20
So the molar mass of strontium hydroxide is, if we google, 121 .63 grams per mole.
00:36
So 10 .40 grams divided by 121 .63 gives us that we have 0 .08551 moles of strontium hydroxide.
00:53
We have to divide that by our volume, which is 59 milliliters.
00:58
To convert that to liters, and then we get that this is a molarity of 1 .449.
01:14
This is then used to titrate a nitric acid reaction solution, sorry.
01:33
And then we're going to produce water and a salt.
01:38
Sr is a 2 +, so this will be no3, 2.
01:44
Okay, so how exactly are we going to balance this? first, we can look at the number of nitrates, correct? there's two nitrates on the right, so we need to add a 2 here.
01:57
And then there are two hydrogens on the left, another 2 from the strontium, so that makes 4 hydrogens, 2 oxygens.
02:10
So this side only has two hydrogens and one oxygen, so we need another 2 here.
02:16
We do our full head count.
02:18
There's one strontium, there's two nitrates, there's one, two, three, four hydrogens, and one oxygen...