00:01
So here if we see we are looking at each statement.
00:04
So the statement a which is here we can say, the n -a -o -h, which is a base, it is here, it is still in the bureate.
00:15
It is still in the bureauet.
00:19
And what we can say, it means that some was left over.
00:31
And here we can say, it means that not all the naoh, it means that not all naah went into the weak acid that will result in the lower modality.
01:00
And if we see here what is happening, the case which is happening further, here we can say, with the bureate with the not completely full with the bureate which is not completely full it will it will create a but let but let at the end of burette and what we can say it will result in the left over which because noh was not there.
01:56
So if we see here further what is happening, we can say there is no indicator in the solution...