1 A thin cylindrical pipe with an inside diameter of 200 mm is 4 mm thick and fitted with end covers. It is subjected to an internal pressure of \( 4,8 \mathrm{MPa} \). Calculate the circumferential and longitudinal stress induced. Which axially applied compressive load would reduce the longitudinal stress to zero? \[ \left[\sigma_{\mathrm{c}}=120 \mathrm{MPa} ; \sigma_{1}=60 \mathrm{MPa} ; 150,79 \mathrm{kN}\right] \]

          1 A thin cylindrical pipe with an inside diameter of 200 mm is 4 mm thick and fitted with end covers. It is subjected to an internal pressure of \( 4,8 \mathrm{MPa} \). Calculate the circumferential and longitudinal stress induced. Which axially applied compressive load would reduce the longitudinal stress to zero?
\[
\left[\sigma_{\mathrm{c}}=120 \mathrm{MPa} ; \sigma_{1}=60 \mathrm{MPa} ; 150,79 \mathrm{kN}\right]
\]

1 A thin cylindrical pipe with an inside diameter of 200 mm is 4 mm thick and fitted with end covers. It is subjected to an internal pressure of 4,8 MPa. Calculate the circumferential and longitudinal stress induced. Which axially applied compressive load would reduce the longitudinal stress to zero?

[σc=120 MPa ; σ1=60 MPa ; 150,79 kN]

Added by Kimberly R.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Aparna Shakti

04/05/2024

Step 1

The formula for circumferential stress in a thin-walled cylinder is: \[ \sigma_c = \frac{P \cdot d}{2 \cdot t} \] where: - \(P = 4.8 \, \text{MPa}\) (internal pressure), - \(d = 200 \, \text{mm} = 0.2 \, \text{m}\) (inside diameter), - \(t = 4 \, \text{mm} = Show more…

Show all steps

Thanks for your feedback!

1 A thin cylindrical pipe with an inside diameter of 200 mm is 4 mm thick and fitted with end covers. It is subjected to an internal pressure of \( 4,8 \mathrm{MPa} \). Calculate the circumferential and longitudinal stress induced. Which axially applied compressive load would reduce the longitudinal stress to zero? \[ \left[\sigma_{\mathrm{c}}=120 \mathrm{MPa} ; \sigma_{1}=60 \mathrm{MPa} ; 150,79 \mathrm{kN}\right] \]