1) A university dean is interested in determining the proportion
of students who receive some sort of financial aid. Rather than
examine the records for all students, the dean randomly selects 200
students and finds that 118 of them are receiving financial aid.
The 95% confidence interval for p is 0.59 ± 0.07. Interpret this
interval.
Group of answer choices
We are 95% confident that between 52% and 66% of the sampled
students receive some sort of financial aid.
We are 95% confident that 59% of the students are on some sort
of financial aid.
We are 95% confident that the true proportion of all students
receiving financial aid is between 0.52 and 0.66.
95% of the students get between 52% and 66% of their tuition
paid for by financial aid.
2) A county clerk wants to estimate the proportion of voters who
will need special election facilities. Suppose a sample of 400
voters was taken. If 150 need special election facilities, what is
the upper confidence limit (UCL) for the 90% confidence interval
for the population proportion of voters who will need special
election facilities. Round your answer to 3 decimal
places.
3) A confidence interval was used to estimate the proportion of
statistics students who are females. A random sample of 72
statistics students generated the following 90% confidence
interval: (0.438, 0.642). Based on the interval above, is the
population proportion of females equal to 0.60?
Group of answer choices
No, and we are 90% sure of it.
Maybe. 0.60 is a believable value of the population proportion
based on the confidence interval.
No. The proportion is 54.17%
Yes, and we are 90% sure of it.