00:02
In this case, we have a 9 kj hanging weight, mass m, which is 9 kg, which is hanging using a pulley.
00:18
And the pulley has another mass of small m, which is 5kg.
00:26
So it is connected using a pulley and it is kept on a flat table.
00:43
This is what we have with us.
00:46
So in this case, here we have taken m to be 5kg, capital m to be 9kg.
00:57
The coefficient of static friction is given to be 0 .200.
01:09
So we have to find out the tension.
01:15
So according to the question we have, you can write that t minus f of k equals to 5a this is 5a this is for the case of for mass 5kg otherwise we can write it as 9g minus t equals to 9a this is for the case of for mass 9 kg so when we add both these equations that is equation 1 and equation 2 so, we're going to add it 1 plus 2.
02:16
What does it give? 9 into 9 .80 minus 0 .2 0 .200 divided by 500 into 9 .80 equals to 14a...