00:01
Hello students, in this question given as a pipe diagram, pipe and tank diagram and all dimensions of pipe is given in the fit.
00:08
The diameter of the first pipe is 4 inch which we have converted into the fit and diameter 2 is 2 inch and diameter rate flow q is equal to flow of the rate of flow of liquid is given here and density viscosity.
00:27
In the first part of the question, we have to write the bernoulli's equation.
00:34
So, p1 upon rho g plus p1 square upon 2g plus z1 is equal to p2 upon rho g plus p2 square upon 2g plus z2.
00:58
This equation is when we considering the friction is 0 then and p1 pressure p1 and p2 are same and initial velocity of the liquid is 0.
01:12
So, this quantity will cancel and this will become 0.
01:16
Now z1 minus z2 will be equal to the height h is equal to p2 square upon 2g.
01:30
Now we will calculate the v2.
01:32
We know that the flow rate is equal to q is equal to area a2 into p2.
01:42
So, a2 at point b is 5 by 4 into diameter d2 is given as 2 inch that means 0 .167 feet that is square into p2 and q value is given in the question 0 .223...