Question

1. An internal expanding shoe brake is given in the figure below. Calculate the force (F) needed to apply 3600 lbf in total braking torque (braking capacity). The shoe is rigid molded asbestos with $f = 0.33$. The shoe is long. Face width, $b$, is 1 in. Direction of rotation is counterclockwise. The distance from center to pin, $a$, is 5.22 in. (40 points) $T = \int frdN = \frac{fP_a b r^2}{\sin \theta_a} \int_{\theta_1}^{\theta_2} \sin \theta d\theta$ $= \frac{fP_a b r^2 (\cos \theta_1 - \cos \theta_2)}{\sin \theta_a}$ $p = \frac{P_a}{\sin \theta_a} \sin \theta$ $M_f = \int fdN(r - a \cos \theta) = \frac{fP_a b r}{\sin \theta_a} \int_{\theta_1}^{\theta_2} \sin \theta (r - a \cos \theta) d\theta$ $M_N = \int dN(a \sin \theta) = \frac{P_a b r a}{\sin \theta_a} \int_{\theta_1}^{\theta_2} \sin^2 \theta d\theta$ $F = \frac{M_N - M_f}{c}$ Self energizing shoe $F = \frac{M_N + M_f}{c}$ Self-de energizing shoe

          1. An internal expanding shoe brake is given in the figure below. Calculate the force (F) needed to apply 3600 lbf in total braking torque (braking capacity). The shoe is rigid molded asbestos with $f = 0.33$. The shoe is long. Face width, $b$, is 1 in. Direction of rotation is counterclockwise. The distance from center to pin, $a$, is 5.22 in. (40 points)

$T = \int frdN = \frac{fP_a b r^2}{\sin \theta_a} \int_{\theta_1}^{\theta_2} \sin \theta d\theta$
$= \frac{fP_a b r^2 (\cos \theta_1 - \cos \theta_2)}{\sin \theta_a}$

$p = \frac{P_a}{\sin \theta_a} \sin \theta$

$M_f = \int fdN(r - a \cos \theta) = \frac{fP_a b r}{\sin \theta_a} \int_{\theta_1}^{\theta_2} \sin \theta (r - a \cos \theta) d\theta$

$M_N = \int dN(a \sin \theta) = \frac{P_a b r a}{\sin \theta_a} \int_{\theta_1}^{\theta_2} \sin^2 \theta d\theta$

$F = \frac{M_N - M_f}{c}$ Self energizing shoe

$F = \frac{M_N + M_f}{c}$ Self-de energizing shoe

1 an internal expanding shoe brake is given in the figure below calculate the force f needed to apply 3600 lbf in total braking torque braking capacity the shoe is rigid molded asbestos with 59018

Added by Madison G.

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