00:02
Okay, this question has different parts ranging from a all the way to c.
00:11
Okay, so let's start by solving a.
00:14
So the work done on the refrigerator can be found from equation w is equal to p into change in time.
00:23
Okay, so solving this, it will be 52 .168 and 286, 400.
00:33
That leaves me with an answer of 4 .51 into 10 raised to power 6.
00:45
Let me just confirm that for you.
00:49
52 .168 into 8640 there.
00:56
4 .51.
01:00
And don't forget the units which are joules.
01:06
That's answer to part a now let's come to part b for part b the energy qc is removed from the freezer and in order to find that we can say qc is equal to 6 .3 into 4 .51 into 10 raise to power 6 and so having that i get qc to be equal to 2 .84 into 10 to power 7 joules now let's come to c for c so see the energy required to convert a mass of water at 20 degrees alchus into a mass of water at 0 degrees alchus can be found by this equation q is equal to mc change in t plugging in our values it will be mc 0 minus 20 and that leaves us an answer of minus 20 mc now let's come to no, sorry, let me just finish up the c part...