00:01
Hello student.
00:02
So we are given some structures here and we have to find out how many stero isomers are possible there.
00:09
Right.
00:10
So first the structure it is given here that is this one.
00:16
This cyclobene cyclic hexane is there.
00:21
Oh is there and one this group is attached there.
00:27
So now we can see here first what are stereo isomer? stereo center first we have to find out.
00:34
Stereo center is that it is related to that carbon atom which have four different substituted.
00:45
Yes, substitution you can say or you can simply you can say four different atoms or molecules or any substitutions.
00:54
Right.
00:55
So now we can see here for example in this case.
00:58
I talk about this carbon.
01:00
So this carbon, it is a stereo carbon.
01:03
You can see here that in one side it is attached oh group is there, right? one is h is there and another side it is ch2c and but here this is cs2 and see from where the branch is attached there.
01:21
Right.
01:22
So therefore we can say this is a chiral carbon or a stereo center.
01:27
Right? and this is zero center.
01:28
This is zero similarly, you can see in here this is also a stereo center, right? see, one carbon is there, that means two diamethyl is attached there, one ch2 and oh is there, one cs2, cs2 is there, right? there are two substitution for and one, another, and the fourth one is hydrogen atom, right? so we can say that these two, or these molecules have two stereosur, these stereos have two stereos centers.
02:01
Fine? now to find out the molecules or possible stereo centers or the stereo isomers, possible stereo isomers, we have one formula that is squared to 2 raise to the power n, where n is the number of stereo center.
02:26
For example, in this case, in this case, the number of stereo centers we have, we just find out that is 2 and is equal to 2.
02:36
So therefore possible isomers in this case will be 2 raised to the power 2.
02:44
That is 4.
02:45
So 4 is the possible isomers for this particular molecule.
02:50
Now let us see the next one.
02:54
So next, in the the next molecule we have this cyclohexane is there one cyclohexane one os group substitution is attached there and one this amine group is attached there right so again let us find out the stereo center you can see here that this one stereo center is there oh h cs2 and cs2 and 1 h is there similarly this is also a stereo center right so here two stereo centers are there.
03:28
Stereo centers are here.
03:31
So we can say that means n is equal to 2.
03:35
Yes.
03:36
So that means possible isomers in this case will be again 2 raised to the power n.
03:42
That means 2 raised to the power 2 is equal to 4.
03:45
Again in this case the number of possible isomers it is here.
03:50
So 4 stereos possible isomers possible in both case.
03:55
Now in the second part we have to draw the mirror image of particular molecules and we have to find out that these are achyral or achyral.
04:07
So first molecule we have this one.
04:11
One carbon is there, right? one carbon is there and one group is, one methyl group is attached which is above the plane and c -o -o -h is there.
04:22
This oh is there and one molecule or one substitute is present which is ch3 and it is below the plane.
04:32
Now we have to draw the mirror image of this particular compound and we know that how to draw that mirror image.
04:41
We just have to follow the rules, right? that distance of the image and the distance of the object will be equal.
04:51
Right? coh is there therefore cooh will form here.
04:56
Next is oh is there.
04:59
Oh is there and ch3 is there and one methyl group which is above the plane it will form here...