00:01
A buffer solution is prepared which contains hf and n.
00:03
What is the ph? so k -a is given 3 .5 multiplied this.
00:11
So we have to need to calculate p -k -a.
00:14
P -k -a is equal to minus log k -a.
00:18
So minus log k -a value is this, 3 .5 multiplied 10 raised to the power minus 4.
00:27
So what is come out here? it will be equal to 3 .45 right so now we know that ph equal to pka plus log salt divided by acid because it is the buffer solution 3 .45 plus log salt by acid salt is given 1 .4 divided by 1 right so what is the value 1 .4 it is it will be equal to 3 .59 so value of the ph is equal to 3 .59.
01:07
In the second part, what will be the ph of the solution if hcl is added? if in this buffer solution hcl is added, then the nef will react because n .af is the base.
01:21
So n .f plus hcl.
01:24
That will give nacl plus hf.
01:27
Initially, what is the concentration of both? hf is the 1 molar.
01:32
N .f is given 1 .4.
01:35
Concentration of the buffer solution of the hcl is given to...