00:01
Hello.
00:02
So in this question it is given to us that we are having 16 % barium chloride by mass and the density is also given to us.
00:12
So we have to find out the molarity, the molifaction and the molality at the given temperature.
00:19
So let's start solving it.
00:21
So firstly it is given to us that we are having 16 % barium chloride by mass.
00:27
It clearly means that we are having 16 grams.
00:33
B.
00:34
Acl2 that is barium chloride in 100 grams solution we are having 16 grams b .a .c .l .2 in 100 grams of solution.
00:52
It means that if you are talking about the solvent, so the solvent is 100 minus 16, that is 84 grams.
01:07
Okay.
01:08
And if we want to find out the volume, so the solvent is 100 minus 16, that is 84 grams.
01:10
Of this 100 gram of solution we know that density will be equal to mass divided by volume and density is given to us as 1 .1564 so 1 .1564 is equal to mass that is 100 grams divided by volume so the volume is equal to 100 divided by 1 .1564.
01:49
So 100 divided by 1 .1564 came out to be equal to 86 .48 m.
02:02
Okay.
02:03
So now what we will do is we will find out firstly the molarity.
02:08
So if you talk about molarity, so the molarity is always.
02:12
Equal to number of moles of solute divided by volume of the solution in liters.
02:22
And if we talk about the number of moles, so the number of moles will be given mass divided by molar mass.
02:35
The number of moles will be equal to given mass that is 16 divided by molar mass of barium chloride that is 208 .23.
02:49
So 16 divided by 208 .23 will came out to be equal to 0 .0768.
03:03
Okay.
03:05
So these are the number of modes.
03:08
So we will just put the value in the formula for molarity.
03:12
So the molarity is equal to number of moles that is 0 .0768 divided by volume of the solution and we have found out the volume of the solution is 86 .48 ml.
03:31
So it will be 86 .48 multiplied by 10 to the power minus 3 liters.
03:38
So we have 0 .0768 divided by 86 .48...