1) Calculate the total resistance for the following circuits...

1) Calculate the total resistance for the following circuits if $R_1 = 200 Omega$, $R_2 = 400 Omega$, and $R_3 = 600 Omega$. a. Battery $R_1$ $R_2$ $R_3$ $R_1$ Battery $R_2$ $R_3$ b. 2) For the given circuits, determine the current through each resistor and the voltage across each resistor. Then calculate the power supplied by the source and the power dissipated by each resistor. Show that the total power dissipated by the resistors is equal to the power supplied by the source. a. E 10 V $R_1$ 500 $R_2$ 1k $R_3$ 1.5k $R_1$ 3k E 10V $R_2$ 1500 GND $R_3$ 500 GND b. 3) Answer the following questions for the given RC circuit. $V_s = 12 V$; $R = 40 kOmega$; $C = 100 mu F$ R a. Describe what happens when the switch is closed. $V_s$ C b. What is the voltage on the capacitor after one time constant ($ au$)? c. How long does it take the capacitor to fully charge?

Transcript

00:01 All right, dear learners, in part one, let's draw the circuit diagram.

00:08 The first circuit diagram.

00:10 Here we have a source.

00:12 With this source, we have one resistor connected this way.

00:16 The other register connected this way.

00:19 And the last register is connected with this way.

00:22 It is connected with the negative terminal of the battery.

00:25 All right.

00:26 And this register, it is r1.

00:30 This register is r2 and this register is r3.

00:35 We have to find the equivalent resistance because they are connected in parallel so the formula should be 1 over r equivalent is equal to 1 over r1 plus 1 divided by r2 plus 1 divided by r3.

00:51 Now simply plug in the values 1 divided by r1 it is given it is of 200 ooms plus this resistor it is of 400 ohms plus this resistor it is of 600 oombs plus this resistor it is of 600 all right this is 1 divided by our equivalent or r equivalent is equal to that is simply be equal to 120 divided by 11 so from here are equivalent or the total resistance of this circuit comes out to be 109 .0 .0 so in the second part we have a source here this is a positive this is negative terminal with this we have one resistor connected here the other register is connected here and the last register is connected this way now let's label the diagram this is r1 this is r2 and this is r3 now the resistors are connected in series so the total resistance will be the sum of all the resistances it is simple now simply plug in the values what is r1 it is 200 r2 is 400 and r3 is 600 so our equivalent comes out to be 1200 ohms all right so this is part a now let's move to part b all right let's draw the circuit diagram first for part b or in the part two here we have a source with this source we have a register and another register connected in parallel and one more register is connected in parallel with this source all right this emf source it is of 10 volts this register it is r1 and it is a 500 ohm this register it is r2 and this is of thousand ohms and this register r3 this is a of 1500 oms all right the current flowing through this register r1 is i1 the current flowing through r2 is i2 and the current flowing through r3 is i3 and let's say the current of the source is denoted with i first of all let's find the current through resistor 1 that is simply equal to total voltage there is 10 because they are connected in parallel so this 10 volt will be on all the resistors 10 volt divided by the resistance is 500 ohms that would simply equal to 0 .02 ampers so this is the current through i i1 the current through i2 will similarly be equal to 10 volts the voltage 10 volts divided by the resistance is thousand ohms so from here the current comes out to be 0 .01 ampere through r2 the current through r3 would simply be equal to 10 volts divided by the resistance of r3 is 1500 ohms this would be equal to 0 .0026 ampers so this is the current through all the resistances now let's say the voltage of the resistor across r1 is v1 the voltage across r2 is v2 and the voltage across r3 is v3 so they are connected in parallel if the registers are connected in parallel their voltage is same and these registers are connected with the source this world it means their voltage would be same and this is equal to 10 volts it means 10 volts on r1 10 volts on r2 and 10 words on r3 all right let's find the power dissipated in resistor 1 let's say that is pr1 that would simply be equal to its current square time its resistance all right the current of resistor 1 is 0 .02am squared its resistance is 500 oh home so it means its power come comes out to be 0 .2 watts all right similarly the power dissipated in r2 is equal to the current passing through that is i2 it's squared times its resistance that is r2 now simply plug in the values i2 is 0 .01 squared r2 is thousand ohms so from here the power dissipated in r2 comes out to be 0 .066wam's so from here the power dissipated in r2 comes out to be 0 .66 similarly the power drop across r3 is equal to the current flowing through it there is this one 0 .0066 it's squared times its resistance there is 1500 all light so this would come out to be 0 .066 watts all right sorry this was 0 .3 watts this is my mistake i apologize so this is 0 .3 watts and this is 0 .06 watts.

07:06 All right.

07:07 So it means the total power dissipated across all the registers is equal to the power dissipated across r1 plus the power dissipated across r2 plus the power dissipated across r3.

07:22 Now after putting all the values, 0 .2 watt plus 0 .3 watt plus 0 .06 watt...

Question

Please give Ace some feedback