Question

1.) Complete the table. \begin{tabular}{c|c|c|c|c|c} $x$ & $P(x)$ & $xP(x)$ & $(x - \mu)$ & $(x - \mu)^2$ & $(x - \mu)^2P(x)$ \\ \hline 3 & 0.1 & & & & \\ \hline 6 & 0.2 & & & & \\ \hline 9 & 0.3 & & & & \\ \hline 12 & 0.1 & & & & \\ \hline 15 & 0.3 & & & & \\ \hline $\sum P(x) = 1$ & $\sum xP(x) = $ & & & $\sum (x - \mu)^2P(x) = $ \\ \end{tabular}

          1.) Complete the table.
\begin{tabular}{c|c|c|c|c|c}
$x$ & $P(x)$ & $xP(x)$ & $(x - \mu)$ & $(x - \mu)^2$ & $(x - \mu)^2P(x)$ \\
\hline
3 & 0.1 &  &  &  &  \\
\hline
6 & 0.2 &  &  &  &  \\
\hline
9 & 0.3 &  &  &  &  \\
\hline
12 & 0.1 &  &  &  &  \\
\hline
15 & 0.3 &  &  &  &  \\
\hline
$\sum P(x) = 1$ & $\sum xP(x) = $ &  &  & $\sum (x - \mu)^2P(x) = $ \\
\end{tabular}

1.) Complete the table.

x P(x) xP(x) (x - μ) (x - μ)^2 (x - μ)^2P(x)

3 0.1

6 0.2

9 0.3

12 0.1

15 0.3

∑ P(x) = 1 ∑ xP(x) = ∑ (x - μ)^2P(x) =

Added by Vicente B.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Qudsiya Anis

09/28/2023

Step 1

To find the mean, we use the formula: \[ \mu = \sum_{i} x_i \cdot P(x_i) \] \[ \mu = 3(0.1) + 6(0.2) + 9(0.3) + 12(0.1) + 15(0.3) \] \[ \mu = 0.3 + 1.2 + 2.7 + 1.2 + 4.5 \] \[ \mu = 9.9 \] Show more…

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1.) Complete the table. [ egin{array}{|c|c|c|c|c|c|c|} hline x & P(x) & xP(x) & (x-mu) & (x-mu)^2 & (x-mu)^2P(x) \ hline 3 & 0.1 & 0.3 & & & \ 6 & 0.2 & 1.2 & & & \ 9 & 0.3 & 2.7 & & & \ 12 & 0.1 & 1.2 & & & \ 15 & 0.3 & 4.5 & & & \ hline end{array} ] 2x-P(x)= \ E[P(x=1)] \ E[xP(x)=