00:01
In this problem, we have been given that there is a solenoid and the solenoid consists of n turns and the radius of the solenoid is r that's given.
00:12
And the current that is flowing, let's take that as i.
00:17
And we need to determine the magnetic field inside the solonite.
00:23
So for this, we're going to make use of ampere circuit law.
00:27
And according to that magnetic field into dl, line integral of.
00:34
Dl.
00:35
So for that if we just consider a small empyrean loop here, we will see that magnetic field into line integral of dl that will be equal to mu not into the current contained.
00:46
So since there are n number of turns, we're going to take here n.
00:50
And here we observe that line integral of dl that will just be the length.
00:55
So in that case, b will be mu not into i into n.
01:00
And here is the number of turns per unit length.
01:05
So this is the expression of magnetic field inside the solenoid.
01:09
And now we have to figure out the self -inductance l of the solenoid.
01:16
So as we have already figured out the magnetic field and that magnetic field is mu not into n into i divided by l...