00:01
Hello everyone, let's proceed to solve this question.
00:03
So, in the first part, we have given the total energy that's u is simply equal to 3 apsulin.
00:11
So this is what the total energy given to us is.
00:18
Now, we need to find the number of microsate.
00:21
So the number of microstate, so the number of microstate, it will simply be equal to the possible number the possible combination with total energy u to be 3 epsilon so if we see the total number of combination is 0 and 3 absalom and 3 absalom and the rest 2 are at 0 again 0 3 absalom and 0 again so again 3 absalom 0 2 epsilon sumo 2 absalom 0 and finally absalom and another will be 0 2 epsilon epsilon and zero absolute to epsilon and the rest three will be zero epsilon all right so we take this zero epsilon to epsilon zero epsilon two epsilon two epsilon and absin all right and finally absalom absalom so one two three four five six seven eight nine and one more will be there so okay let's let me just find out.
01:59
So 0 .03, epsilon, 3 absalom, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 ,000, epsilon, 0, 0, absolute, 0 ,000, absolute.
02:11
So one will again be 0, absalom to epsilon.
02:19
Alright.
02:21
So total micro -states will be 10.
02:24
So total number of microstate will be simply 10.
02:36
So now in case 2, when the total energy, u will simply be equal to 5 aftelon, so total energy is 5 absalom, now the number of microstates, what be the number of microstates? so this way simply be equal to 0 comma 0, comma 5 absalom, comma 5 absalom and let's see what the rest will be.
03:11
So in this way 5 option can be arranged...